Abstract
The collinear 4Σ pathway for the state‐specific O+(4S)+N2(X 1Σg+) →NO+(X 1Σ+)+N(4S) reaction has been surveyed with ab initio calculations. A ninety‐nine configuration, fifteen orbital multiconfiguration self‐consistent field (MCSCF) wave function, involving the use of a double‐zeta plus polarization one‐electron basis, was developed for the long range 4Σ state. This long range 4Σ state has the character of O++N2 for long RNO, or of N+NO+ for long RNN, and is for most geometries, the lowest, or 1 4Σ, state. The ab initio exothermicity computed with the present wave function is 0.93 eV, compared to an accurate experimental value of 1.10 eV. The saddle‐point in the energy surface is 8.0 eV above O++N2, with critical values of R*NN=1.48±0.02 Å and R*NO =1.38±0.02 Å. These values are 0.38 and 0.32 Å greater than the equilibrium bond lengths of N2(X 1Σg+) and NO+(X 1Σ+). The present wave function reproduces the experimental bond lengths of these two diatomics to within 0.01 Å when the third atom is removed to 500 a.u. (264.6 Å). Preceding the barrier on the O++N2 side is an appreciable polarization well. With the present wave function the attributes of this well are D° (N2–O+) =0.38 eV, RNNE=1.108 Å, RNOe =2.350 Å, ϑeNNO=180°, keNN=24.679 md/Å, keNO=0.295 md/Å, kϑ=0.0366 md/Å. There is also a smaller polarization well on the N+NO+ side. Although the ion–atom interaction is more stable at Cs the latter well is bound by 0.02 eV at 180° with ReNN=3.34 Å, and ReNO=1.07 Å.