Abstract
The method described previously for the solution of the wave equation of two-electron atoms has been applied to the 1S1 and 2S3 states of helium, with the purpose of attaining an accuracy of 0.001 cm1 in the nonrelativistic energy values. For the 1S1 state we have extended our previous calculations by solving determinants of orders 252, 444, 715, and 1078, the last yielding an energy value of -2.903724375 atomic units, with an estimated error of the order of 1 in the last figure. Applying the mass-polarization and relativistic corrections derived from the new wave functions, we obtain a value for the ionization energy of 198 312.0258 cm1, as against the value of 198 312.011 cm1 derived previously from the solution of a determinant of order 210. With a Lamb shift correction of -1.339, due to Kabir, Salpeter, and Sucher, this leads to a theoretical value for the ionization energy of 198 310.687 cm1, compared with Herzberg's experimental value of 198 310.82±0.15 cm1.